in a quadrilateral angle a 60 b 80 c is thrice of d
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Angle A + B + C + D = 360°.
(Angle sum property )
A = 60° B = 80° C = 3x D = x
Therefore 60 + 80 + 3x + x = 360°
4x = 360 - 140 = 220°
x = 220/4 = 55°
Therefore
A = 60°
B = 80°
C = 3x = 3×55 = 165°
D = x = 55°
(Angle sum property )
A = 60° B = 80° C = 3x D = x
Therefore 60 + 80 + 3x + x = 360°
4x = 360 - 140 = 220°
x = 220/4 = 55°
Therefore
A = 60°
B = 80°
C = 3x = 3×55 = 165°
D = x = 55°
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