Question

In a quadrilateral d = 6cm, h1 = 5cm, h2 =3cm then A = .... cm2.

Answer 1

Step-by-step explanation:

$\\ area \: of \: a \: quadrilaterl = \frac{1}{2} \times d(h1 + h2)$

$= \frac{1}{2} \times 6\times(5 + 3)cm$

$= 3 \times 8 \\ = {24cm}^{2}$

hence a=24cm^2

hope it helps u

please mark me as brainliest