In a quadrilateral if angles are arranged in ascending order then each next angle becomes twice the first. Find the least angle of the quadrilateral.
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I'm assuming that each angle becomes twice of the preceding angle otherwise this question doesn't make sense. So to set up that equation, if you take "x" as the least angle. then:
x + 2x + 2(2x) + 2(2(2x)) = 360
Each value is twice that of the previous value. So now when you solve,
x + 2x + 2(2x) + 2(2(2x)) = 360
x + 2x + 4x + 8x =360
15x = 360
x = 360/15
x= 24°
x + 2x + 2(2x) + 2(2(2x)) = 360
Each value is twice that of the previous value. So now when you solve,
x + 2x + 2(2x) + 2(2(2x)) = 360
x + 2x + 4x + 8x =360
15x = 360
x = 360/15
x= 24°
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