In a quadrilateral PKMN, P=(2x+42), K=(x+22), M=(x+38), N=(2x+12) [ P, K, M and N are ANGLES in degree]. what is the measure of angle P?
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Answer:
124°
Step-by-step explanation:
total angle of quadrilateral= 360
hence P+K++M+N= 360
(2x+42)+(x+22)+(x+38)+(2x+12)= 360
6x+114=360
6x= 360-114=246
6x= 246
x=246/6
x=41
now by putting x value for P :
P = {2(41)+42}=82+42
P= 124°
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