Math, asked by lucky446675, 7 months ago

In a quadrilateral PKMN, P=(2x+42), K=(x+22), M=(x+38), N=(2x+12) [ P, K, M and N are ANGLES in degree]. what is the measure of angle P?​

Answers

Answered by pawanpazi1987
0

Answer:

124°

Step-by-step explanation:

total angle of quadrilateral= 360

hence P+K++M+N= 360

(2x+42)+(x+22)+(x+38)+(2x+12)= 360

6x+114=360

6x= 360-114=246

6x= 246

x=246/6

x=41

now by putting x value for P :

P = {2(41)+42}=82+42

P= 124°

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