in a quadrilateral PQRS angle P + angle R =2 (angle Q+angle S) if angle P is equal to 40 degree then find the measure of angleR
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Answered by
32
We know sum is360, & opposite angles are supplementary.
then
P+R+2(Q+S)=360
R=180-40=120
then
P+R+2(Q+S)=360
R=180-40=120
soha7:
this is wrong because angle p +q+r+s =360 not p+r+2(q+r)
Answered by
20
given -- angle p + angle r = 2( angle q + angle s ) .
angle p = 40 .
To find ----- measure of angle r .
Proof ---- angle p + angle r + 2 (angle q + angle s)=360 .
(total angle sum of a quadrilateral is 360°).
40° + angle r +2 ( angle q + angle s ).
40° + angle r + angle q + angle s = 360°/2.
" " " " =180°
Therefore angle r + angle q + angle s =180°-40°
angle r = 120°
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