In a quadrilateral PQRS, <P=65, <Q=125.If <R:<S::2:3, find the angles R and S.
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Answer:
P=65
Q=125
sum of all angle in quadrilateral =360°
In quad pqrs p=65,q=125 and rs are in the ratio=R:S::2:3
so r:s be 2x and 3x
P+q+r+s=360°
65+125 +2x+3x=360°
190+5x=360°
5x=360-190
5x=170
x=170÷5=34
R=2x=2×34=68
S=3x=3×34=102
Answered by
1
quadrilateral =360
so p+q+r+s=360
65+125+r+s 360
190+r+s=360
r+s=360-190
=170
r:s=2:3
2x+3x=170
5x=170
x=170/5
x=34
r=2(34)=68
s=3(34)=102
so65+125+68+102=360
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