In a quadrilateral PQRS, PQ = PS and PR is the bisector of ∠P. Show that ∆PQR ≌ ∆PSR. Is QR = SR?
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Answer:
yes QR=SR( CPCT=Corresponding part of congruent triangle)
Step-by-step explanation:
In ∆PQR and ∆PSR
PQ=PS( given)
PR is common
angle SPR= angle QPR( PR bisects angle P)
thus ∆PQR is congruent to ∆ PSR(SAS)
and PQ=PS(cpct
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