In a quadrilateral PQRS, ZP= 120° and ZQ= ZR= ZS, find ZQ, ZR<br />and ZS.<br />
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Answer:
sum of angles of quadrilateral is 360
let ZQ=ZR=ZS=X
Now ZP+ZQ+ZR+ZS=360
120+X+X+X=360
120+3X=360
3X=360-120
3X=240
X=240/3
X=80
hence ZQ=ZR=ZS=80
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