in a quadrilateral the greatest side and the smallest sides are opposite to each other less prove that the adjacent angle to the greatest side is smaller than its opposite side
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Step-by-step explanation:
Let ABCD be a parallelogram, with angleA = α and angleB = β.
Prove that angleC = α and angleD = β.
α + β = 180° (co-interior angles, AD || BC),
so angleC = α (co-interior angles, AB || DC)
and angleD = β (co-interior angles, AB || DC).
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