In a quadrilateral the length of one diagonal is 12cm and the perpendicular distances to this diagonal from the opposite vertexes are 9cm and 6cm. if the length of the other diagonal of this quadrilateral is 18cm, find the sum of the perpendicular distances to this diagonal from the opposite vertices.
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Answers
Answered by
1
Answer:
390 cm square
Step-by-step explanation:
1/2×40(12+7.5)=20×19.5=390cm
Answered by
0
Answer:
Area of quadrilateral =
1/2*d1*(h1+h2)
Step-by-step explanation:
Area= 1/2(12)(9+6)
= 80cm^2
Similarly,
Area= 1/2(18)(h1+h2)
=9(h1+h2)
=80 (proved above)
Therefore,
h1+h2= 80/9cm
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