In a quadrilateralABCD, ւD =150˚ and ւA = ւB = ւC. Finf ւA , ւB and ւC
Answers
Answered by
1
Answer:
The given Quadrilateral ABCD can be drawn by following the steps.
Step 1: Draw a line AB=4.2cm
Step 2: With A as the centre and radius =8cm draw an arc.
Step 3: with B as the centre and radius =6cm draw another arc cutting previous arc. Label this point as C
Step 4: Join BC
Step 5: With A as the centre and radius =5cm draw an arc.
Step 6: with C as the centre and radius =5.2cm draw another arc cutting previous arc. label this point as D
Step 7: join CD and AD.
Answered by
1
Given:
Given: zA = 150*
We know that sum of all angles of
quadrilateral is equal to 360
Therefore,zÁ + B+ 2C+ zD = 360*
- 150 + ¿B+ C + zD= 360*
150+ 3LB = 360 [As B = 2C= 2D]
32B = 360 -
50°
-2B= Z10
3
2B= LC = 2D = 70*
Similar questions