Math, asked by rajendiransanjay, 3 days ago

In a quadrilateralABCD, ւD =150˚ and ւA = ւB = ւC. Finf ւA , ւB and ւC​

Answers

Answered by patilgaytri1984
1

Answer:

The given Quadrilateral ABCD can be drawn by following the steps.

Step 1: Draw a line AB=4.2cm

Step 2: With A as the centre and radius =8cm draw an arc.

Step 3: with B as the centre and radius =6cm draw another arc cutting previous arc. Label this point as C

Step 4: Join BC

Step 5: With A as the centre and radius =5cm draw an arc.

Step 6: with C as the centre and radius =5.2cm draw another arc cutting previous arc. label this point as D

Step 7: join CD and AD.

Answered by dharmbir04698
1

Given:

Given: zA = 150*

We know that sum of all angles of

quadrilateral is equal to 360

Therefore,zÁ + B+ 2C+ zD = 360*

- 150 + ¿B+ C + zD= 360*

150+ 3LB = 360 [As B = 2C= 2D]

32B = 360 -

50°

-2B= Z10

3

2B= LC = 2D = 70*

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