Math, asked by sparshagrawal73, 9 months ago

In a quadrilatonal ABCD, the angles
LA, LB, LC & LD are in the ratio 1:2:3:4
Find the measure of each angle of
the quadalatonal​

Answers

Answered by sethrollins13
22

Given :

  • ∠A , ∠B , ∠C , ∠D are in the ratio 1:2:3:4

To Find :

  • Measure of each angle of Quadrilateral.

Solution :

\longmapsto\tt{Let\:\angle{A}=1x}

\longmapsto\tt{Let\:\angle{B}=2x}

\longmapsto\tt{Let\:\angle{C}=3x}

\longmapsto\tt{Let\:\angle{D}=4x}

Now ,

As we know that Sum of all angles of a quarilateral is 360° . So ,

\longmapsto\tt{\angle{A}+\angle{B}+\angle{C}+\angle{D}=360\degree}

\longmapsto\tt{1x+2x+3x+4x=360\degree}

\longmapsto\tt{10x=360\degree}

\longmapsto\tt{x=\cancel\dfrac{360}{10}}

\longmapsto\tt\bf{x=36\degree}

So , The Value of x is 36°..

Therefore :

\longmapsto\tt{Measure\:of\:\angle{A}=1(36)}

\longmapsto\tt\bf{36\degree}

\longmapsto\tt{Measure\:of\:\angle{B}=2(36)}

\longmapsto\tt\bf{82\degree}

\longmapsto\tt{Measure\:of\:\angle{C}=3(36)}

\longmapsto\tt\bf{108\degree}

\longmapsto\tt{Measure\:of\:\angle{D}=4(36})

\longmapsto\tt\bf{144\degree}

Answered by ItzDeadDeal
6

Answer:

Given :

∠A , ∠B , ∠C , ∠D are in the ratio 1:2:3:4

To Find :

Measure of each angle of Quadrilateral.

Solution :

 \red{\longmapsto\tt{Let\:\angle{A}=1x}}

 \pink{\longmapsto\tt{Let\:\angle{B}=2x}}

\longmapsto\tt{Let\:\angle{C}=3x}

 \blue{\longmapsto\tt{Let\:\angle{D}=4x}}</p><p>

Now ,

As we know that Sum of all angles of a quarilateral is 360° . So ,

 \pink{\longmapsto\tt{\angle{A}+\angle{B}+\angle{C}+\angle{D}=360\degree}}

 \green{\longmapsto\tt{1x+2x+3x+4x=360\degree}}

 \gray{\longmapsto\tt{10x=360\degree}}</p><p>

 \red{\longmapsto\tt{x=\cancel\dfrac{360}{10}}}

 \orange{\longmapsto\tt\bf{x=36\degree}}

So , The Value of x is 36°..

Therefore :

\longmapsto\tt{Measure\:of\:\angle{A}=1(36)}</p><p>

\longmapsto\tt\bf{36\degree}

\longmapsto\tt{Measure\:of\:\angle{B}=2(36)}

 \orange{\longmapsto\tt\bf{82\degree}}

 \red{\longmapsto\tt{Measure\:of\:\angle{C}=3(36)}}

 \pink{\longmapsto\tt\bf{108\degree}}

</p><p> \green{\longmapsto\tt{Measure\:of\:\angle{D}=4(36}}

  \red{\longmapsto\tt\bf{144\degree}}</p><p>

 \huge \rm \pink{Hence  \: done !!}

Similar questions