Question

in a quardilatral ABCD , BD =20 cm , perpendicular from A and C on BD are 7cm and 9cm respectively. Calculate the area of given quardilatral. ​

Answer 1

Two triangles exist

We can find the area of both.

$\frac{1}{2} *20*7+\frac{1}{2} *20*9=70+90=160$

So the area is 160cm².