In a queue, a is eighteenth from the front while b is sixteenth from the back. If c is twenty-fifth from the front and is exactly in the middle of a and b, then how many persons are there in the queue?
Answers
Answer: A's position from front is 18th
B's position from back is 16th
Since , C is exactly in the middle of A and B
Therefore, Person between A and C = person between B and C
Now, person between A and C (including C) = 25 - 18 = 7
Person between B and C (excluding C ) = 7-1 = 6
So, total person in a queue = 18 + 7 + 6 + 16 = 47
Given : In a queue, A is 18th from the front while Bis 16th from the
last . C is 25th from the front and is exactly in the middle of A and B
To Find : number of people in the queue
Solution:
A is 18th from front
C is 25th from front
C is exactly in middle of A and B
=> 25 = (18 + B)/2
=> B = 32nd
B is 32nd from front
Bis 16th from the last.
=> 31 person ahead of B
15 person behind B
One person is B
Total person = 31 + 1 + 15 = 47
47 people are in queue.
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