Math, asked by sulakshanasonavane29, 10 months ago

in a queue of 4 persons Akhil is standing ahead of jivan and Jyoti .Jyoti is not the last person in the queue how many different combinations are possible?
a.3
b.4
c.5
d.6

Answers

Answered by Anonymous
2

Answer:

4 may be the right answer

Answered by yuvi200506
2

Answer:

the answer is 6

Step-by-step explanation:

Akhil is in front of Jivan and Jyoti is  between them and let the fourth person be X so the possible combinations are six

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