Math, asked by daddubhai45, 11 months ago

in a race Nadeem starts to run when Punit had gone 1.76metres away.Nadeem and Punit in traverse 760 meter in 5 minutes and 6 minutes respectively. how far Nadeem will meet Punit.​

Answers

Answered by amitnrw
1

Nadeem will meet Punit at 10.56 m

Step-by-step explanation:

Nadeem starts to run when Punit had gone 1.76metres away

Let say Punit travel Distance = D m  when they meet

=> Nadeem has covered Distance in same time   = D + 1.76 m

Nadeed speed  = 760/5  =  152 m/min

Time taken by Nadeem to cover D+1.76 m   = (D + 1.76)/152  min

Punit speed  = 760/6  =  380/3 m/min

Time taken by Punit to cover D m   = D/(380/3) min = 3D/380  min

(D + 1.76)/152  = 3D/380

=> 380D  + 668.8  = 456D

=> 76D =  668.8

=> D = 8.8 m

Nadeem has covered Distance = 8.8 + 1.76  =  10.56 m

Nadeem will meet Punit at 10.56 m

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