in a race Nadeem starts to run when Punit had gone 1.76metres away.Nadeem and Punit in traverse 760 meter in 5 minutes and 6 minutes respectively. how far Nadeem will meet Punit.
Answers
Nadeem will meet Punit at 10.56 m
Step-by-step explanation:
Nadeem starts to run when Punit had gone 1.76metres away
Let say Punit travel Distance = D m when they meet
=> Nadeem has covered Distance in same time = D + 1.76 m
Nadeed speed = 760/5 = 152 m/min
Time taken by Nadeem to cover D+1.76 m = (D + 1.76)/152 min
Punit speed = 760/6 = 380/3 m/min
Time taken by Punit to cover D m = D/(380/3) min = 3D/380 min
(D + 1.76)/152 = 3D/380
=> 380D + 668.8 = 456D
=> 76D = 668.8
=> D = 8.8 m
Nadeem has covered Distance = 8.8 + 1.76 = 10.56 m
Nadeem will meet Punit at 10.56 m
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