in a race of 300 m, p beats m by 30 m and q by 50 m. if m and q are running a race of 200m with the samr speed as before, then by how many approximate meters will m beat q?
Answers
Answer:
m beat q by approx 15 m
Step-by-step explanation:
in a race of 300 m, p beats m by 30 m and q by 50 m
p completes 300m
m completes 300 - 30 = 270 m
q complets 300 - 50 = 250 m
if m completes 270m then q completes = 250 m
if m completes 1 m then q completes = 250/270
if m completes 200 m then q completes = (250/270) * 200
= 185. 2 m
m beat q by 200 - 185.2 = 14.8 m
Approx by 15 m
Answer:
14.815 m
Step-by-step explanation:
p beats m by 30 m and q by 50 m ⇒ when p completed 300 m, m has completed 270 m and q has completed 250 m.
In other words time taken by p to complete 300 m, time taken by m to complete 270 m and time taken by q to complete 250 m is equal. ----- (1)
Let speed of m and q be 'a' m/s and 'b' m/s respectively.
Using: time = distance/speed
Time taken by m to complete 270 m = 270/a
Time taken by q to complete 250 m = 250/b
From 1: 270/a = 250/b
⇒ a/b = 270/250 = 27/25 ---------------------------- (2)
NOW: The race is of 200 m and speed of m and q are same as before
distance = 200 m
speed of m = 'a' m/s
speed of q = 'b' m/s
Time taken by m to complete 200 m = 200/a seconds
In 200/a seconds, distance traveled by q = speed x time
= b x 200/a
putting a = (27/25) b in the above expression
Distance traveled by q = b x (200 x 25)/ (27 x b)
= 185.185 m
Hence, we can conclude that when m has completed 200 m, p was at a distance of 185.185 m
'm' beats 'q' by 200 - 185.185 = 14.815 m