Question

In a race, Puja and Jakir start to complete from the same point and same time on a circular track of length of diameter is 28 meter. When Puja finishes the race at the competition by 4 revolution, Jakir is one revolution behind. Let us calculate how many meters is the length of the race and by how many miters Puja beats Jakir.​

Answer 1

Answer:

Diameter of the track= 28 m

Radius of track (r) = 14 m

circumference = 2×Pie×r

=2×22/7×14=88 meters

total Length of track for 1 round = 88 m

pooja completed 4 rounds = 88×4=352 m

Jakir is one revolution behind = 88×3=264 m

Total difference between pooja and jakir = 352-264=88 m

Step-by-step explanation:

Diameter of the track= 28 m

Radius of track (r) = 14 m

circumference = 2×Pie×r

=2×22/7×14=88 meters

total Length of track for 1 round = 88 m

pooja completed 4 rounds = 88×4=352 m

Jakir is one revolution behind = 88×3=264 m

Total difference between pooja and jakir = 352-264=88 m