Question

In a railway compartment, 6 seats are vacant on a bench. In how many ways can 3 passengers sit on them.please describe briefly

Answer 1

$\underline{\textsf{To find:}}$

$\textsf{The number of ways can 3 passengers sit on 6 seats are vacant on a bench}$

$\underline{\textsf{Solution:}}$

$\mathsf{Consider,}$

$\begin{array}{|c|c|c|c|c|c|}\cline{1-6}Seat-1&Seat-2&Seat-3&Seat-4&Seat-5&Seat-6\\\cline{1-6}\end{array}$

$\textsf{The first passenger can choose a seat among 6 different vacants in 6 ways}$

$\textsf{After choosing the first person, there are 5 vacants}$

$\therefore\textsf{The second person can choose a seat in 5 different ways}$

$\textsf{Similarly, the third person can choose a seat in 4 different ways}$

$\textsf{By fundamental principle of multiplication,}$

$\textsf{Total number of ways can 3 passengers sit on the bench}$

$\mathsf{=6{\times}5{\times}4}$

$\mathsf{=120\;ways}$

$\underline{\textsf{Answer:}}$

$\textsf{Total number of ways is 120}$

$\underline{\textsf{Find more:}}$

Write all 3 digit numbers using 2 3 4 taking each digit only once

https://brainly.in/question/1854576

Write all 3 digit numbers using 2 3 4 taking each digit only once

https://brainly.in/question/1854576

Answer 2

Answer:

120

Step-by-step explanation:

Formula: nCr*r!

Solution:

6C3*3

=6!*3!/3!*3!

= 6*5*4*3*2*1*3*2*1/3*2*1*3*2*1

= 120

Hope this helps!!