in a rain water harvesting eth e rain water from a roof of 22 .20m drins to cylindical tank having diameter of 2 and height 3.5 fimd height of rainflall
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Here is the solution:
r = radius of cylindrical vessel = 1 m
h = height of cylindrical vessel = 3.5 m
Therefore volume of cylindrical vessel = 22/7 x 12 x 3.5 m3 = 11m3
Let the rain fall be y m. Then
Volume of water on roof = volume of cuboid of base 22m x 20m and height ym
= (22 x 20 x y) m3
Now volume of water on roof = volume of water in cylinder
=> (22 x 20 x y) = 11
y = 11 /(22 x 20)
= 1/40 m
= 100/40 cm
= 2.5 cm
Therefore height of water on roof = 2.5 cm
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r = radius of cylindrical vessel = 1 m
h = height of cylindrical vessel = 3.5 m
Therefore volume of cylindrical vessel = 22/7 x 12 x 3.5 m3 = 11m3
Let the rain fall be y m. Then
Volume of water on roof = volume of cuboid of base 22m x 20m and height ym
= (22 x 20 x y) m3
Now volume of water on roof = volume of water in cylinder
=> (22 x 20 x y) = 11
y = 11 /(22 x 20)
= 1/40 m
= 100/40 cm
= 2.5 cm
Therefore height of water on roof = 2.5 cm
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