Question

In a rainy day , 96% of the students were present . If the number of absent student is 168 , find the total strength. ​

Answer 1

$\huge{\boxed{\mathfrak{\underline{Solution:}}}}$

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$\large{\underline{\underline{\sf{Mathematics}}}}$

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Let the total no of students be valued as 100%.

Then, 94% of it are present.

So,

(100 - 94) = 6 % of them are absent .

No of students who were absent  = 174

So, we can say , 6% equals to 174

So, 1 % equals to $\dfrac{174}{6}$ = 29

And 100% equals to = 29 × 100 = 2900

$\large{\underline{\underline{\sf Answer :}}}$

Hence, Total Strength is 2900.

Answer 2

Let the Total Strength of the School be : P

Mentioned : 96% of the students were present

$\mathrm{\implies Students\;present\;in\;the\;School = (P \times 96\%)}$

$\mathrm{\implies Students\;present\;in\;the\;School = \left(P \times \dfrac{96}{100}\right)}$

$\mathrm{\implies Students\;present\;in\;the\;School = \dfrac{96P}{100}}$

Mentioned : Number of Students absent = 168

☢  Total Strength = Students Present + Students Absent

$\mathrm{\implies P = \dfrac{96P}{100} + 168}$

$\mathrm{\implies P - \dfrac{96P}{100} = 168}$

$\mathrm{\implies \dfrac{100P - 96P}{100} = 168}$

$\mathrm{\implies \dfrac{4P}{100} = 168}$

$\mathrm{\implies P = \dfrac{168 \times 100}{4}}$

$\mathrm{\implies P = ({42 \times 100})}$

$\mathrm{\implies P = 4200}$

$\mathrm{\implies Total\;Strength\;of\;School = 4200}$