Question

In a random mating population the frequency of
homozygous dominant individuals are 0.36.
What will be the frequency of dominant allele
(A) and recessive allele (a)?
(1) A = 0.3, a = 0.7 (2) A = 0.6, a = 0.4
(4) A = 0.2, a = 0.8
(3) A = 0.8, a = 0.2​

Answer 1

It is given that, the population frequency of dominant allele (p) is 0.7. Hence, the population frequency of recessive allele (q) will be 1 - 0.3 = 0.7.

We know that p

2

+ 2pq + q

2

= 1, where p

2

is frequency of homozygous dominant phenotype, 2pq is frequency of heterozygous dominant phenotype and q

2

is frequency of homozygous recessive phenotype.

Hence, frequency of homozygous dominant phenotype (p

2

) will be 0.7

2

= 0.49.

Thus, the correct answer is '0.49.'

Option a is the correct answer