In a random sample of 1000 students, p= 0.80 (or 80%) were in favor of longer hours at the school library. The standard error of p(the sample proportion) is (approximately)
Answers
Answered by
1
Given : In a random sample of 1000 students,
p= 0.80 (or 80%) were in favor of longer hours at the school library.
To Find : The standard error of p(the sample proportion) is (approximately)
Solution:
The standard error of p = √ [p (1-p) / n)]
p = 0.8
1 - p = 1 - 0.8 = 0.2
n = 1000
=> The standard error of p = √ [0.8 (0.2) / 1000)]
=> The standard error of p ≈ 0.01265
Learn More:
The mean and variance of binomial distribution are 4 and 4/3 ...
brainly.in/question/3037214
If the probability of selecting a defective bolt is 0.1, find (1) the mean
brainly.in/question/11773467
Similar questions