In a random sample of 400 fruit flies, how many should have wing lengths of > 4.4mm if the mean is 4mm and the standard deviation is 0.2?
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Answer:10
Explanation:
In a normal (Gaussian) distribution, σ=68%, 2σ=95%
the mean is 4 mm, so ±0.2mm would be 1 standard deviation. meaning 68% of measured wings will be between 3.8 mm and 4.2 mm.
±0.4mm would be two standard deviations, so 95% of measured wings will be between 3.6 mm and 4.4 mm.
The question only asks about the upper end.|dw:1400770931080:dw|
This upper end is half of the rest (from 95%), which is 2.5%.
so 2.5% of 400 individuals is 10.
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