Question

in a random temperature scale Z water freezes at 20°Z and boils at 220°Z . Find the boiling point of a liquid in this scale if it boils at 60°C​

Answer 1

The boiling point of a liquid in Z scale if it boils at 60°C is 140°Z.

We know, $\frac{X - LP}{UP - LP}$ = Constant for all scale; where X is a certain scale, LP stands for lower point and UP stands for Upper point.

• In Z scale,

the upper point = 220°Z

the lower point = 20°Z

Difference is (220 - 20) = 200°Z

• In Celcius scale,

the upper point = 100°C

the lower point = 0°C

Difference is (100 - 0) = 100°C

• Now,

   $\frac{Z - 20}{200}$ = $\frac{60 -0}{100}$

⇒Z = 120 + 20 = 140°Z.