Math, asked by kurmasuribabu, 6 months ago

In a rational number of the form p/q,q must be a non zero integer.True or false ​


kurmasuribabu: hi everyone

Answers

Answered by Anonymous
22

Answer:

TRUE

Explanation:

Yes, if a rational number is in the form p/q, then q should not be equal to 0.

Why so?

Division by zero is not valid/allowed. We can't predict if a number is divided by 0, what would be the quotient.

Let us suppose, 1 is divided by zero and the question is a

1/0 = a

1 = a × 0

1 = 0 !

which is not possible.

As 0 × a will never be any number except 0.

So, q should be non zero integer.

NOTE: p could be any integer including 0. It will give the answer as 0 and 0 is a rational number.

0/1 = 0/2 = 0/3 = 0

Answered by Anonymous
11

\huge\bold{\mathbb{QUESTION}}

In a rational number of the form {\dfrac{p}{q}}, \,q must be a non-zero integer.

True or False

\huge\bold{\mathbb{TO\:FIND}}

Whether the given statement is true or false.

\huge\bold{\mathbb{ANSWER}}

True

\huge\bold{\mathbb{EXPLANATION}}

In a rational number of the form {\dfrac{p}{q}}, \,q must be a non-zero integer.

Because division by 0 is not possible or is undefined. We can't find the quotient on dividing any number by 0.

For example, {\dfrac{x}{0}} is undefined.

\:\:\:\:\:\;\; Here, x is a non-zero integer.

To understand clearly, let's divide 2 by 0 and take the quotient as x.

So, {\dfrac{2}{0}}=x.

Here,

  • 2 is the dividend.

  • 0 is the divisor.

  • x is the quotient.

We know that:

\;\;\;\;\;\;\;\; \boxed{\boxed{\sf Dividend=Quotient\times Divisor}}

\sf Quotient\times Divisor

=x\times0

=0 \;\;\; \small{\{\sf Any\:number\times 0=0\}}

But, 2\neq 0

\therefore \sf Dividend\neq Quotient\times Divisor

So, the division is not possible.

\huge\bold{\mathbb{EXPLORE\:MORE}}

  • Division is the distribution of something into a number of equal parts. For example, a cake is divided into 4 equal parts.

  • It is the opposite of multiplication.

  • Division has 4 parts, namely dividend, divisor, quotient and remainder.
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