in a rational number , twice the numerator is 2 more than the denominator . If 3 is added to each , the numinator and the denominator , the new fraction is 2/3 . Find the original numbers?
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Answer:
numerator= -4
denominator= 10
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let the numerator and denomination be x and y respectively.
According to question ( ATQ)
2x = y+2
2x-y =2 .............(1)
ATQ
x+3/y+3=2/3
3(x+3)=2(y+3)
3x+9=2y+6
3x-2y= -3.............(2)
multiplication of equation(1)by 2 and then subtract from equation (2) we get,
4x-2y=4.............(3)
SUBTRACTION
4x-2y=4
3x-2y= -3
ans >>> x=7
putting x in equation (3) we get,
28-2y=4
28-4=2y
2y=24
y=12
THEREFORE THE ORIGINAL NUMBER IS
x/y=7/12.......
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