Question

In a reaction, 12g of carbon and 16g of oxygen reacted to produce carbon dioxide. Calculate the amount of carbon dioxide produced. What is the limiting reagent in the production of carbon dioxide?

Answer 1

C + O2 ------> CO2

here, it is clear that 1 mole of carbon reacts with 1 mole of oxygen and forms 1 mole of carbon dioxide. or you can say that, 12g of carbon reacts with 32g of oxygen and forms 44g of carbon dioxide.

but weight of oxygen is given just 16g . so, oxygen is limiting reagent.

now , 32g of oxygen forms 44g of carbon dioxide.so, 1g of oxygen forms 44/32 = 11/8 g of carbon dioxide.

so, 16g of oxygen forms 11/8 × 16 =22g of carbon dioxide.

hence, weight of carbon dioxide = 22g

Answer 2

C + O2 ------> CO2

here, it is clear that 1 mole of carbon reacts with 1 mole of oxygen and forms 1 mole of carbon dioxide. or you can say that, 12g of carbon reacts with 32g of oxygen and forms 44g of carbon dioxide.

but weight of oxygen is given just 16g . so, oxygen is limiting reagent.

now , 32g of oxygen forms 44g of carbon dioxide.so, 1g of oxygen forms 44/32 = 11/8 g of carbon dioxide.

so, 16g of oxygen forms 11/8 × 16 =22g of carbon dioxide.

hence, weight of carbon dioxide = 22g