Question

in a reaction 2a+b→a2b 2 moles of a and 2 moles of b are in one litre vessel . 0.5 mole of A2B are present, find Kc

Plz help.... First one to correctly answer will be marked BRAINLIEST

Answer 1

Answer:

The expression for the equilibrium constant is A+2B⇔C+2D.

The expression for the equilibrium constant is  

[A][B]%2

[C][D]  

2

 

​  

.

The following table lists the equilibrium concentration of various species.

A        

B  

         C                     D

Initial  

1

2

         0

0

Change

-x

-2x

         x

2x

Equilibrium    

1-x

2-2x

         x

2x

But [C]=0.4=x.

Hence, the number of moles of A,B,C and D in 0.5 L are 06,1.2,0.4 and 0.8 respectively.

The molar concentrations of A,B,C and D are 1.2, 2.4, 0.8 and 1.6 respectively.

Substitute the values in the expression for the equilibrium constant.

K  

c

​  

=  

1.2×(2.4)  

2

 

0.8×(1.6)  

2

 

​  

=  

27

8

​  

.

Explanation:

Answer 2

Answer:

hellooo

Explanation:

same as above mate