Question

In a reaction, 2A → Products, the concentration of A decreases from
$0.5mol {L }^{ - 1} \: \: to \: \: 0.4 {molL}^{ - 1}$
in 10min. Calculate the rate during this interval.
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Answer 1

Answer:

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Answer 2

$\text{\huge{\red{\underline{Answer:-}}}}$

0.005 mol / L min.

$\text{\large{\orange{\underline{Given:-}}}}$

• Reaction, 2A → Products.

• Concentration of A, 0.5 mol/L → 0.4 mol/L

• Time = 10 min

$\text{\large{\orange{\underline{Solution:-}}}}$

Rate of reaction = Rate of disappearance of A

= –½ [∆A]/T

= –½ (0.4 – 0.5) mol/L ÷ 10 min

= 0.005 mol/ L min.

Which is the required answer.