Question

In a reaction 2X + Y = X2Y , The reactant X will disappear at

Answer 1

Explanation:

2X + Y → Z

Rate =

2dt

−d[X]

=

dt

−d[Y]

=

dt

+d[Z]

2dt

−d[X]

=2×

dt

d[Z]

= 2 × 0.05 = 0.1 mol L

−1 min −1

Answer 2

Given: a chemical equation $2X+Y=X_{2} Y$

To find: the rate to disappearance of X.

Step-by-step method:

Step 1 of 2

When a reactant reacts, it disappears and when a product is formed, if appears. The sing for disappearance id (-) minus and that of appearance is (+) plus.

$2X+Y=X_{2} Y$

$-\frac{1}{2} \frac{d[X]}{dt} =-\frac{d[Y]}{dt} =\frac{d[X_{2}Y ]}{dt}$

Step 2 of 2

$-\frac{d[X]}{dt} =-2\frac{d[Y]}{dt} \\-\frac{d[X]}{dt} =2\frac{d[X_{2}Y ]}{dt}$

The reactant X will disappear at twice the rate at which Y will decrease.

Also, it will disappear at twice the rate at which product is formed.