Chemistry, asked by ksrd420, 1 year ago

in a reaction 4.6 gm of barium chloride reacted with 3.4 gm of sodium sulphate.the products were 2.8 gm sodium chloride and 5.2 gm of barium sulphate.the reaction takes place as follows barium chloride+sodium sulphate=sodium chloride+barium sulphate show that the above observation is in agreement with law of conservation of mass.state the law

Answers

Answered by patelbino29
0

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Answered by madeducators6
1

Given:

The reaction, that take place

barium chloride+sodium sulphate=sodium chloride+barium sulphate

(Na2SO4 + BaCl2 → NaCl + BaSO4)

mass of barium chloride used = 4.6g

mass of sodium sulphate used = 3.4g

mass of sodium chloride formed = 2.8g

mass of barium sulphate formed = 5.2g

To Prove:

The data is in agreement with the law of conservation of mass

Explanation:

Now, we know that according to the law of conservation of energy,

"the mass in an isolated system can neither be created nor be destroyed but can transform from one form to another."

thus, the mass of reactants = mass of products

mass of barium chloride used + mass of sodium sulphate used = mass of sodium chloride formed + mass of barium sulphate formed

4.6 + 3.4 g of reactants  = 2.8 + 5.2 g of products

8g of reactants = 8g of product

thus, the given observation is in agreement with the law of conservation of energy.

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