In a reaction, 5.3 g of sodium carbonate reacted with 6 g of ethanoic acid. The products were 2.2 g of
carbon dioxide, 0.9 g water and 8.2 g of sodium ethanoate. Show that these observations are in agreement
with the law of conservation of mass,
Sodium carbonate + ethanoic acid —> sodium ethanoate + carbon dioxide + water.
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According to the question,
Na
2
CO
3
+CH
3
COOH→CO
2
+H
2
O+CH
3
COONa
Mass of reactants =5.3+6=11.3 gm
Mass of products =2.2+0.9+8.2=11.3 gm
This shows, that during a chemical reaction, the mass of reactant = mass of the product.
Hence, it shows the law of conservation of mass.
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