In a reaction, 5.3 g of sodium
carbonate reacted with 6 g of
ethanoic acid. The products were
2.2 g of carbon dioxide, 0.9 g
water and 8.2 g of sodium
ethanoate. Show that these observations are in agreement
with the law of conservation of
mass.
sodium carbonate + ethanoic acid
→ sodium ethanoate + carbon
dioxide + water
Answers
Answered by
18
Answer:
According to the question,
Na
2
CO
3
+CH
3
COOH→CO
2
+H
2
O+CH
3
COONa
Mass of reactants =5.3+6=11.3 gm
Mass of products =2.2+0.9+8.2=11.3 gm
This shows, that during a chemical reaction, the mass of reactant = mass of the product.
Hence, it shows the law of conservation of mass.
Answered by
3
Answer:
According to the question,
Na
2
CO
3
+CH
3
COOH→CO
2
+H
2
O+CH
3
COONa
Mass of reactants =5.3+6=11.3 gm
Mass of products =2.2+0.9+8.2=11.3 gm
This shows, that during a chemical reaction, the mass of reactant = mass of the product.
Hence, it shows the law of conservation of mass.
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