Question

In a reaction, 5.3 g of sodium carbonate reacted with 6 g of ethanoic acid, The
product were 2.2 g of carbon dioxide 0.9 g of water & 8.2 g Sodium ethanote.
Show that these observations are in agreement with the law of conservation of
mass.​

Answer 1

Answer:

In the given reaction, sodium carbonate reacts with ethanoic acid to produce sodium ethanoate, carbon dioxide, and water

sodium carbonate + ethanoic acid †’ sodium ethanoate + carbon dioxide + water

Mass of sodium carbonate=5.3g (given)

Mass of ethanoic acid=6g(given)

Mass of carbon dioxide=2.2g(given)

Mass of water=0.9g(given)

Mass of sodium ethanoate=8.2g(given)

Now total mass before reaction=(5.3g+6g)=11.3g

Now total mass after reaction=(8.2g+2.2g+0.9g)=11.3g

Total mass before reaction=total mass after reaction

Therefore the given observation is in agreement with law of conservation of mass.