In a reaction, 5.3 g of sodium carbonate reacted with 6 g of
ethanoic acid. The products were 2.2 g of carbon dioxide, 0.9 g water
and 8.2 g of sodium ethanoate. Show that these observations are in
agreement with the law of conservation of mass.
Sodium carbonate + ethanoic acid sodium ethanoate + carbon +
dioxide + water
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Answered by
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Answer:
According to the question,
Na 2
CO 3
+CH 3
COOH→CO 2
+H 2
O+CH 3
COONa
Mass of reactants =5.3+6=11.3 gm
Mass of products =2.2+0.9+8.2=11.3 gm
This shows, that during a chemical reaction, the mass of reactant = mass of the product.
Hence, it shows the law of conservation of mass.
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