In a reaction, 5.3 g of sodium
carbonate reacted with 6 go
acetic acid. The products were
2.2 g of carbon dioxide, .0.9 g
water and 8.2 g of sodium
acetate. Show that these observation are in agreement with the law of conservation of mass
sodium carbonate + acetic acid => sodium acetate + carbon dioxide + water
Answers
Answer:
Explanation: HI SAKSHI
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sodium carbonate + acetic acid → sodium acetate + carbon dioxide + water
5.3g 6g 8.2g 2.2g 0.9g
Now,
Total Mass on the Left Hand Side = 5.3g + 6g = 11.3g
Total Mass on the Right Hand Side = 8.2g + 2.2g + 0.9g = 11.3g
As Mass on the LHS is equal to RHS, the observation is in agreement with the law of conservation of mass.
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Sodium carbonate + acetic acid → Sodium acetate + carbon dioxide + water
Solution:
Sodium carbonate + acetic acid → Sodium acetate + carbon dioxide + water
5.3g 6g 8.2g 2.2g 0.9g
As per the law of conservation of mass, the total mass of reactants must be equal to the total mass of products
As per the above reaction, LHS = RHS i.e., 5.3g + 6g = 2.2g + 0.9 g + 8.2 g = 11.3 g