In a reaction, 5.3 g of sodium carbonate reacts with 6 g of ethnic acid. The products were 2.2 g of carbon dioxide, 0.9 g water and 8.2 g of sodium ethanoate. show that this observation are in agreement with the law of conservation of mass
Answers
SOLUTIONS:
All that we have to do in this problem is to calculate the mass of reactants and products separately, and then compare the two.
If the two masses are equal, then the law of conservation of mass gets verified. The given reaction can be written as :-
⇒ Na₂CO₃ + CH₃COOH
⇒ C₂H₃NaO₂ + CO₂ + H₂O
(i) Sodium carbonate and ethanoic acid are reactants.
So, Mass of reactants = Mass of sodium carbonate + mass of ethanoic acid.
⇒ 5.3 + 6 = 11.3 g __________(1)
(ii) Sodium ethanoate, carbon dioxide and water are products.
So, Mass of products = Mass of sodium ethanoate + mass of carbon dioxide + mass of water.
⇒ 8.2 + 2.2 + 0.9
⇒ 11.3 g ____________(2)
We find that the mass of reactants is 11.3 g animal products is also 11.3 g. Since the mass of products is equal to the mass of reactants, the given data verifies the law of conservation of mass.