Question

In a reaction, 5.3g of sodium carbonate reacted with 6 g of acetic acid. The products were 2.2 g of carbon dioxide, 0.9 g water and 8.2 g of sodium acetate. Show that these observations are in agreement with the law of conservation of mass.Sodium carbonate + acetic acid → Sodium acetate + carbon dioxide + water​

Answer 1

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Sodium carbonate + acetic acid → Sodium acetate + carbon dioxide + waterSodium carbonate + acetic acid → Sodium acetate + carbon dioxide + water

5.3g 6g 8.2g 2.2g 0.9g

As per the law of conservation of mass, the total mass of reactants must be equal to the total mass of

products

As per the above reaction, LHS = RHS i.e., 5.3g + 6g = 2.2g + 0.9 g + 8.2 g = 11.3 g

Hence the observations are in agreement with the law of conservation of mass.

Answer 2

Answer:

In the given reaction, sodium carbonate reacts with ethanoic acid to produce sodium ethanoate, carbon dioxide, and water

sodium carbonate + ethanoic acid †’ sodium ethanoate + carbon dioxide + water

Mass of sodium carbonate=5.3g (given)

Mass of ethanoic acid=6g(given)

Mass of carbon dioxide=2.2g(given)

Mass of water=0.9g(given)

Mass of sodium ethanoate=8.2g(given)

Now total mass before reaction=(5.3g+6g)=11.3g

Now total mass after reaction=(8.2g+2.2g+0.9g)=11.3g

Total mass before reaction=total mass after reaction

Therefore the given observation is in agreement with law of conservation of mass.

Explanation:

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