Question

In a reaction,5.3g of sodium carbonate reacted with 6g of ethanoic acid. The products were 2.2g of carbon dioxide, 0.9g of water and sodium ethanoate. What is the expected weight of sodium ethanoate ? This data is in agreement with which law of chemical Combinations?

Answer 1

Here is your answer:

The given reaction is:

5.3 g Na2CO3+6g of CH3COOH forms 2.2g of CO2 +0.9g of H2O + X g of C2H3NaO2

According to the law of conservation of mass the mass of RHS is equal to the mass of LHS

Therefore mass of Sodium Ethanoate is

11.3g -3.1g =8.2g

Therefore the mass of sodium ethanoate is 8.2g

The data is in agreement with the law of conservation of mass

Answer 2

Answer:

Heya !

Here is your answer ============================================================================

>> Mass of sodium carbonate = 5.3 g (given)

Mass of ethanoic acid = 6 g (given)

Mass of sodium ethanoate = 8.2 g (given)

Mass of Carbon dioxide = 2.2 g (given)

Mass of water = 0.9 g (given)

Now, total mass before the reaction = (5.3 + 6) g

= 11 . 3 g

And, total mass after the reaction = (8.2 + 2.2 + 0.9 ) g

= 11.3 g

total mass before the reaction = total mass after the reaction.

Hence, the given observations are in agreement with the law of conservation of mass.

Hope it helps !!! : )