Question

in a reaction 5.3g of sodium carbonate reacted with 6g of Ethonic acide. the product were 2.2g of carbon dioxide ,0.9 g water and 8.2 g of sodium ethonate . show that this observations are in agreement with the with the law of conservation of mass , sodium carbonate + ethonic acid - sodium ethanoate + carbon dioxide + water .​

Answer 1

Answer:

hey mate here is ur answer

Explanation:

In the given reaction, sodium carbonate reacts with ethanoic acid to produce sodium ethanoate, carbon dioxide, and water

sodium carbonate + ethanoic acid †’ sodium ethanoate + carbon dioxide + water

Mass of sodium carbonate=5.3g (given)

Mass of ethanoic acid=6g(given)

Mass of carbon dioxide=2.2g(given)

Mass of water=0.9g(given)

Mass of sodium ethanoate=8.2g(given)

Now total mass before reaction=(5.3g+6g)=11.3g

Now total mass after reaction=(8.2g+2.2g+0.9g)=11.3g

Total mass before reaction=total mass after reaction

Therefore the given observation is in agreement with law of conservation of mass.

Answer 2

Answer:

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EXPLANATION:

Heya !

Here is your answer ============================================================================

>> Mass of sodium carbonate = 5.3 g (given)

Mass of ethanoic acid = 6 g (given)

Mass of sodium ethanoate = 8.2 g (given)

Mass of Carbon dioxide = 2.2 g (given)

Mass of water = 0.9 g (given)

Now, total mass before the reaction = (5.3 + 6) g

= 11 . 3 g

And, total mass after the reaction = (8.2 + 2.2 + 0.9 ) g

= 11.3 g

total mass before the reaction = total mass after the reaction.

Hence, the given observations are in agreement with the law of conservation of mass.

Hope it helps !!! : )