Question

In a reaction, 5.3g of sodium carbonate reacted with 6g of ethanoic acid. The products were 2.2g of carbon dioxide, 0.9g water and 8.2g of sodium ethanoate. show that these observations are in agreement with the law of conservation of mass. Sodium carbonate + ethanoic acid → sodium ethanoate + carbon dioxide + water

Answer 1

Answer- Sodium carbonate (5.3g) + Ethanoic acid (6g)---> Carbon dioxide (2.2g) + Water (0.9g) + Sodium ethanoate (8.2g)

According to law of conservation of mass,

In a chemical reaction, mass can neither be destroyed or created.

⇒ Mass of reactants= Mass of Products

In the above reaction, reactants are Sodium carbonate and ethanoic acid while products are carbon dioxide, water and sodium ethanoate.

Mass of reactants= mass of sodium carbonate + mass of ethanoic acid

= 5.3 g + 6 g

= 11.3 g

Mass of products= mass of carbon dioxide + mass of water + mass of sodium ethanoate

= 2.2 g + 0.9 g + 8.2 g

= 11.3 g

As 11.3 g = 11.3 g, so mass of reactants = mass of products

Therefore, law of conservation of mass is satisfied.

Please mark as the BRAINLIEST answer if helpful.

Answer 2

Answer:

Heya !

Here is your answer ============================================================================

>> Mass of sodium carbonate = 5.3 g (given)

Mass of ethanoic acid = 6 g (given)

Mass of sodium ethanoate = 8.2 g (given)

Mass of Carbon dioxide = 2.2 g (given)

Mass of water = 0.9 g (given)

Now, total mass before the reaction = (5.3 + 6) g

= 11 . 3 g

And, total mass after the reaction = (8.2 + 2.2 + 0.9 ) g

= 11.3 g

total mass before the reaction = total mass after the reaction.

Hence, the given observations are in agreement with the law of conservation of mass.

Hope it helps !!! : )