.In a reaction 5.3g of sodium carbonate reacted with 6g of acetic acid.The products were 2.2g of carbon dioxide,0.9g of water and some sodium ethnoade .What will be the weight of sodium ethnoade?????Reply fast.
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reaction=5.3+6.0=11.3
products=11.3 - (2.2+0.9)=11.3-3.1=8.2
sodium ethnoade=8.2
products=11.3 - (2.2+0.9)=11.3-3.1=8.2
sodium ethnoade=8.2
Answered by
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Answer:
Heya !
Here is your answer ============================================================================
>> Mass of sodium carbonate = 5.3 g (given)
Mass of ethanoic acid = 6 g (given)
Mass of sodium ethanoate = 8.2 g (given)
Mass of Carbon dioxide = 2.2 g (given)
Mass of water = 0.9 g (given)
Now, total mass before the reaction = (5.3 + 6) g
= 11 . 3 g
And, total mass after the reaction = (8.2 + 2.2 + 0.9 ) g
= 11.3 g
total mass before the reaction = total mass after the reaction.
Hence, the given observations are in agreement with the law of conservation of mass.
Hope it helps !!! : )
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