Question

In a reaction, 7.89g of sodium bicarbonate reacted with 12.091 g of hydrochloric acid and forms 6.36 g of sodium chloride, 5.701 g of water and some amount of carbon dioxide. Find the mass of carbon dioxide evolved in the reaction

Answer 1

According to law of conservation of mass;

7.89 + 12.091............6.36 + 5.701 + co2

19.981........12.061 + co2

7.92.......co2

Answer 2

Given:-

→ Mass of Sodium bicarbonate that

reacted = 7.89g

→ Mass of Hydrochloric acid that

reacted = 12.091g

→ Mass of Sodium Chloride

formed = 6.36g

→ Mass of water formed = 5.701g

To find:-

→ Mass of Carbon-dioxide evolved in the

reaction.

Solution:-

The balanced chemical equation for the reaction is :-

NaHCO₃ + HCl → NaCl + H₂O + CO₂

In the given reaction, reactants are :-

• Sodium bicarbonate [NaHCO₃]

• Hydrochloric acid [HCl]

In the given reaction, products are :-

• Sodium Chloride [NaCl]

• Water [H₂O]

• Carbon dioxide [CO₂]

______________________________

Now according to Law of Conservation of mass, we know that there is no change in mass in a chemical reaction :-

Mass of reactants = Mass of products

Let the required mass of CO₂ be 'x' grams. Hence :-

=> 7.89 + 12.091 = 6.36 + 5.701 + x

=> 19.981 = 12.061 + x

=> x = 19.981 - 12.061

=> x = 7.92g

Thus, 7.92g of Carbon dioxide was evolved in the reaction.