Question

In a reaction, A+B→Product, rate is doubled when the concentration of B is doubled, and rate increases by a factor of 8 when the concentrations of both the reactants (A and B) are doubled, rate law for the reaction can be written as

Answer 1

Answer:

rate=k[A]^2[B]

Explanation:

When the conc of B is doubled, the rate is doubled. So, Order wrt [B] is 1

When the conc of both reactants are doubled, rate becomes 8 times. So, Order wrt [A] is 2.

rate=k[A]^2[B ]

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