in a reaction of calcium carbonate, calcium oxide and carbon oxide is prepared, if mass of calcium carbonate is 123gm and calcium oxide formed is 36 gm then mass of carbon dioxide is : option a)90 b)87 c)88 d)36
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Chemical reaction for decomposition of calcium carbonate is :
CaCO
3
→CaO+CO
2
Molar mass of CaCO
3
=100g/mol
Molar mass of CaO=56g/mol
Molar mass of CO
2
=44g/mol
According to law of conservation of mass:
Mass of CaCO
3
= Mass of CaO + Mass of CO
2
If we have one mole of calcium carbonate it will decompose to give one mole of calium oxide and one mole of carbon dioxide.
56 g of CaO is obtained from decomposition of 100 g of CaCO
3
.
So 1.4 g of CaO is obtained from decomposition of [(100×1.4)÷56=2.5g] of CaCO
3
.
Mass of CO
2
= (2.5−1.4) g = 1.1 g
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