Question

In a reaction vessel ,0.184g of NaOH is required to be added for completing the reaction how many milliters of 0.150M NaOH solution should be added for this reaction​

Answer 1

Answer: 30.7 ml

Explanation: Dear Student,

       Molar mass of NaOH = 40g/mol

       1000 ml of NaOH solution contains 0.15 mol = 0.15*40 = 6g.

       It means that 6 g NaOH present in 1000 mL.

       0.184g  NaOH will be present in

       = 1000/6*0.184 = 184/6 = 30.7 mL

Hope it helps

With Regards

Answer 2

Answer:

30.6 ml

Explanation:

Given mass of NaOH = 0.184 g

Number of moles = 0.184/40 g = 0.0046 moles

Molarity is defined as the number of moles present in 1 Liter of solution.

Given Molarity = 0.150 M

⇒ 1 Liter of NaOH solution has 0.150 moles of NaOH.

⇒ 0.150 moles of NaOH is present in 1 liter of NaOH solution.

From the question, we require 0.0046 moles of NaOH.

⇒ 0.0046 moles of NaOH is present in (1/0.150) x 0.0046 Liter of NaOH solution

= 0.0306 Liter = 30.6 ml