Question

. In a recent Barangay election, Mr. Reyes won as Barangay Chairman with 3,074
votes. If there are 5,800 voters in the barangay, what percentage voted for Mr.
Reyes?​

Answer 1

Given:

In a recent Barangay election, Mr. Reyes won as Barangay Chairman with 3,074  votes

If there are 5,800 voters in the barangay

To find:

What percentage voted for Mr.  Reyes?​

Solution:

It is given that → Mr. Reyes won with 3,074  votes in the Barangay election

i.e., No. of voters who voted for Mr. Reyes in the election were = 3074

The total no. of voters in the Barangay election were = 5800

Therefore, considering all the 5800 votes were valid votes in the Barangay election, we get  

The percentage of voters voted for Mr. Reyes is,

= $[\frac{No. \:of\: voters\:voted \:for \: Mr.\: Reyes}{Total \:no.\: of\: voters}] \times 100$

= $[\frac{3074}{5800}] \times 100$

cancelling the zeros from numerator and denominator

= $\frac{3074}{58}$

= $\bold{53\%}$

Thus, 53% of voters voted for Mr. Reyes in the recent Barangay election.

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Answer 2

HELLO DEAR,

GIVEN:- In an certain Barangay election, Mr .Reyes won as Barangay election with 3074 votes.

And total no. Of votes are 5800.

To find by what percent votes Mr. Reyes won.

SOLUTION:- Total no. of votes = 5800.

Election won by Mr. Reyes by total no. of votes= 3074.

Percentage of no. of votes Mr. Reyes

( total no. of votes got Mr Reyrs)× 100

got=_________________________

( Total no. Votes)

=( 3074×100)

___________

(5800)

= 0.53×100

= 53%.

Therefore Mr. Reyes won Barangay election by 53% votes.

I HOPE IT'S HELP YOU DEAR,

THANKS.