Question

In a rectangle ABCD, AB = 12 m
and AC = 13 m. Find the peri-
meter of the rectangle ABCD.​

Answer 1

Answer:

Answer : 34 m

Step-by-step explanation:

One side = 12 m

Another side = x

Diagnol = 13

According to Pythagoras theorm

a^2 + b^2 = c^2 Accordingly

12^2 + x^2 = 13^2

144 + x^2 = 169

x^2 = 169 - 144

x^2 = 25

x = root of 25

x = 5

So :

First side = 12 m

Second side = 5 m

Perimeter of rectangle = 2 ( a + b ) = 2 ( 12 + 5 ) = 2 ( 17 ) = 34 m is the correct answer for your question

Answer 2

Step-by-step explanation:

in right △ ABC,

AC2=BC2+AB2 …[Pythagoras’s Theorem]

BC=AC2−AB2−−−−−−−−−−√

BC=132−122−−−−−−−−√

BC=169−144−−−−−−−−√

BC=25−−√

BC=5 m

P=2(l+b)

P=2(AB+BC)

P=2(12+5)

P=2(17)

P=34 m