Question

in a rectangle ABCD AB=25 cm BC=15 cm in what ratio bisector of angle C divide AB​

Answer 1

Answer:

2 : 3

Step-by-step explanation:

in a rectangle ABCD AB=25 cm BC=15 cm in what ratio bisector of angle C divide AB​

Let say CE is  bisector of angle C

∠C = 90°

Bisector of ∠C = 45°

in Δ CEB

∠BCE = 45° & ∠B = 90°

=> Tan 45° =  BE /BC

=> 1 = BE/15

=> BE = 15 cm

AB = 25 cm   AB = AE + BE

=> 25 = AE + 15

=> AE = 10 cm

AE : BE :: 10 : 15

=> AE : BE :: 2 : 3

bisector of angle C divide AB​ in 2:3  ratio

Answer 2

Answer:

2:3

Step-by-step explanation:

(AB=25cm) , (BC=15cm) given

Let say CE is bisector of angle C

angle C= 90degree

Bisector of angle C=45degree

inDCEB

angle BCE= 45degree and angle B = 90degree

= tan45degree = BE÷ BC

=1= BE÷ 15

=BE=15cm.

AB=25cm ,AB= AE+BE

= 25= AE+ 15

= AE =10 cm

= AE: BE:: 10:15

= AE: BE::2:3

bisector of angle C divide AB in 2:3 ratio